austin3515 Posted February 8, 2015 Posted February 8, 2015 Does anyone have a good template or article on BR&F testing for a match formula based on YOS that has a 1,000 hour/last day rule? Specifically, my question is, do I need to treat people who termed as not benefitting in the higher match rates solely because they terminated (with more than 500 hours). So in my case, the match increases after 5 YOS from 50% of 6% to 100% of 6%. If someone with 7 years terminates, do I need to treat them as not benefitting in the higher rate of match? Since it's coverage testing, I presume the answer is yes. Austin Powers, CPA, QPA, ERPA
Tom Poje Posted February 9, 2015 Posted February 9, 2015 well, 1.401(a)(4)-4(b)(1) says current availability requirement... an employee is treated as benefiting only if the benefit, right, and feature is currently available to the employee. I'd say if they termed that benefit was not available, since they termed > 500 hours they can't be excluded.
Lou S. Posted February 9, 2015 Posted February 9, 2015 I agree with Tom. Which is easy to do because he's usually right.
austin3515 Posted February 9, 2015 Author Posted February 9, 2015 If Tom told me 2 +2 was 5, I'd go buy a new calculator Austin Powers, CPA, QPA, ERPA
Tom Poje Posted February 10, 2015 Posted February 10, 2015 no need to buy a new calculator it already does equal that4x^2 + 4x = 5 * (x+1) * xFactor out x on the left side(4x + 4) * x = 5 * (x+1) * xFactor out 4 on the left side4*(x + 1)* x = 5 * (x + 1) * xBut 4 can be written as (2 + 2)So(2 + 2) * (x + 1) * x = 5 * (x+1) * xDivide both sides by (x + 1)*xAnd you have2 + 2 = 5
austin3515 Posted February 10, 2015 Author Posted February 10, 2015 BRB, I'm running out to Staples Austin Powers, CPA, QPA, ERPA
GMK Posted February 10, 2015 Posted February 10, 2015 And you have 2 + 2 = 5 but only if x does not equal zero or -1. and Austin, if you went paperless (as discussed in another thread), you wouldn't need staples.
John Feldt ERPA CPC QPA Posted February 10, 2015 Posted February 10, 2015 In this equation, x * (x + 1) = 0 Thus, you have (2 + 2) * 0 = 5 * 0 Looks like dividing by zero can really take you places.
GMK Posted February 10, 2015 Posted February 10, 2015 Looks like dividing by zero can really take you places. To infinity ... and beyond! or at least to Staples.
austin3515 Posted February 10, 2015 Author Posted February 10, 2015 This has been one of my favorite threads in a long time... I don't follow the math (I'm pretty sure it was all made up except that I felt I recognized some of it from high school algebra), but it was hilarious anyway. I went back and looked at it again. I'm thinking the algebra is all true but the equation was never "equal" in the first place. Did I get it? Austin Powers, CPA, QPA, ERPA
John Feldt ERPA CPC QPA Posted February 10, 2015 Posted February 10, 2015 Casino Dealer to Austin: 5. Austin: I'll stay. Casino: I suggest you hit, sir. Austin: I also like to live dangerously. Casino: 20 beat your 5 sir. I'm sorry, sir. Austin: Well I must admit, cards aren't my bag, baby.
austin3515 Posted February 10, 2015 Author Posted February 10, 2015 Ah yes, I remember it well... Austin Powers, CPA, QPA, ERPA
Belgarath Posted February 10, 2015 Posted February 10, 2015 Hmph. I say 2 + 2 = 1 How, you may ask? 2 pecks plus 2 pecks equals 1 bushel What's a peck? A quick kiss on the cheek. Math just doesn't make any sense...
GMK Posted February 10, 2015 Posted February 10, 2015 We Benefit from the equation, because Mr. Poje posted it. We know the solution to the equation (given in the first line in Mr. Feldt's post #8) is Right. And the thread Features some clever repartee. Um, what was the question again?
Tom Poje Posted February 10, 2015 Posted February 10, 2015 the math - algebra is correct except for one thing: you can never divide by zero. In this example, x=-1 or 0 hence you can't 'cancel' things out by dividing both sides by either (x + 1) or x because you would be dividing by zero. but I do thank you, I was wondering if and when I would ever be able to work an equation like that into the response. but I could have modified the numbers to be anything 1 = 8, 7 = 3 or whatever. now if I was an actuary then of course it would have been 2 + 2 = "what do you want the answer to be" K2retire 1
austin3515 Posted February 10, 2015 Author Posted February 10, 2015 Tom, an actuary's got nothing on those math skills! Austin Powers, CPA, QPA, ERPA
Tom Poje Posted February 10, 2015 Posted February 10, 2015 ah, Dr Evil told me I could trick you. the formula was 4(x^2) + 4x = 5 * (x+1) * x without dividing (which of course is the fun part because people miss what is going on): 4(x^2) + 4x = 5(x^2) + 5x moving everything to the right side you get 0 = x^2 + x the only answers that work are x = 0 or -1
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